A C++ question, I know int* foo (void) foo will return a pointer to int type how about int &foo (void) what does it return? Thank a lot!

Sep 25, 2010 · That second memory address, then, is expected to hold an int. Do note that, while you are declaring a pointer to an int, the actual int is not allocated. So it is valid to say int *i = …

Jun 16, 2013 · -2 int() is the constructor of class int. It will initialise your variable a to the default value of an integer, i.e. 0. Even if you don't call the constructor explicitly, the default …

Jan 28, 2013 · int array[] = new int[10]; ? Both do work, and the result is exactly the same. Which one is quicker or better? Is there a style guide which recommends one?

Jan 28, 2012 · The real reason that this can happen is that C is a weakly typed language. But unsigned int and int are really different.

Dec 30, 2011 · int a = 5; int& b = a; b = 7; cout << a; prints out 7, and replacing int& b with int &b also prints out 7. In fact so does int&b and int & b. I tested this kind of behavior with a simple …

int is a primitive data type while Integer is a Reference or Wrapper Type (Class) in Java. after java 1.5 which introduce the concept of autoboxing and unboxing you can initialize both int or …

In C#, int and Int32 appear to be the same thing, but I've read a number of times that int is preferred over Int32 with no reason given. Are the two really the same? Is there a reason …

Aug 3, 2008 · In Java, the 'int' type is a primitive, whereas the 'Integer' type is an object. In C#, the 'int' type is the same as System.Int32 and is a value type (ie more like the java 'int'). An integer …

7 c is a double variable, but the value being assigned to it is an int value because it results from the division of two int s, which gives you "integer division" (dropping the remainder). So what …